Aufgabe 2

clear all;
u = 1.6605e-27
u = 1.6605e-27
c = 299792458
c = 299792458
e = 1.609e-19
e = 1.6090e-19
r0 = 1.3e-15
r0 = 1.3000e-15
m131I = 131 * u
m131I = 2.1753e-25

Gegeben

t1 = 30 %Tage
t1 = 30
tHalb_I = 8.0207 %Tage
tHalb_I = 8.0207

a)

N0 = 4.6e22
N0 = 4.6000e+22
Nt = N0 * exp(-log(2) * t1 / tHalb_I)
Nt = 3.4420e+21
mt = Nt *  m131I 
mt = 7.4872e-04

b)

Nrel = 0.9334
Nrel = 0.9334
t2 = 3 %Jahre
t2 = 3
tHalb_Cs = - log(2) * t2 / log(Nrel)
tHalb_Cs = 30.1712

c)

 m0 = 1.874e-12
m0 = 1.8740e-12
 tFisch = 2
tFisch = 2
 relGrenz = 0.1
relGrenz = 0.1000
 
 m2a = m0 * exp(-log(2) / tHalb_Cs * tFisch)
m2a = 1.7898e-12
 
 tFischGut = -log(relGrenz) * tHalb_Cs / log(2)
tFischGut = 100.2265