Aufgabe 7

clear all;
e = 1.602e-19;
h = 6.626e-34;
me = 9.11e-31;
mp = 1.6727e-27
mp = 1.6727e-27
c = 299792458
c = 299792458
sb = 5.67e-8
sb = 5.6700e-08

Gegeben:

T = 4000 %K
T = 4000
r = 1.75e10
r = 1.7500e+10

Maximum

lambdaMax = 2897.8e-6 / T
lambdaMax = 7.2445e-07

Strahlungsleistung

A = 4*pi*r^2
A = 3.8485e+21
P = sb * A * T^4
P = 5.5861e+28