Aufgabe 2

clear all;
e = 1.609e-19;
h = 6.626e-34;
me = 9.11e-31;
c = 299792458
c = 299792458

Gegeben

f = 10e18
f = 1.0000e+19
theta = 180
theta = 180

a) Skizze

b) Wellenlängenzuwachs

lambda_c = h / (me*c)
lambda_c = 2.4261e-12
dLambda = lambda_c * (1 - cosd(theta))
dLambda = 4.8522e-12
lambdaNew = dLambda + c/f
lambdaNew = 3.4831e-11

c) Energie

E = h * c / lambdaNew
E = 5.7030e-15
E_eV = E / e
E_eV = 3.5444e+04

d) Elektron Geschwindigkeit

%v = h/me*(f / c - 1/lambdaNew)
p = h*f / c
p = 2.2102e-23
pNew = E / c
pNew = 1.9023e-23
v = (p - pNew) / me
v = 3.3797e+06