Aufgabe 4

clear all;

Gegeben:

Schaltung 1:
U1 = 10 %V
U1 = 10
Rl_1 = 2 %Ohm
Rl_1 = 2
Rl_2 = 4 %Ohm
Rl_2 = 4
Rl_3 = 4.5 %Ohm
Rl_3 = 4.5000
Rl_4 = 1.5 %Ohm
Rl_4 = 1.5000
Schaltung 2:
U2 = 12 %V
U2 = 12
Rr_1 = 5.5 %Ohm
Rr_1 = 5.5000
Rr_2 = 10 %Ohm
Rr_2 = 10
Rr_3 = 4 %Ohm
Rr_3 = 4
R_innen = 0.25 % Ohm
R_innen = 0.2500

a) Ersatzwiderstand

Schaltung 1:
Rl_ers34 = Rl_3 + Rl_4
Rl_ers34 = 6
Rl_ers = 1/sum(1 ./[Rl_1 Rl_2 Rl_ers34])
Rl_ers = 1.0909
Schaltung 2:
Rr_ers23 = 1/sum(1 ./ [Rr_2 Rr_3])
Rr_ers23 = 2.8571
Rr_ers = Rr_1 + Rr_ers23
Rr_ers = 8.3571

b) Gesamtstromstärke

Schaltung 1:
Il_ges = U1/Rl_ers
Il_ges = 9.1667
Schaltung 2:
Ir_ges = U2/Rr_ers
Ir_ges = 1.4359

c) Einzelströme und Spannungsabfälle

Schaltung 1:
Ul_1 = U1
Ul_1 = 10
Il_1 = Ul_1 / Rl_1
Il_1 = 5
Ul_2 = U1
Ul_2 = 10
Il_2 = Ul_2 / Rl_2
Il_2 = 2.5000
Ul_ers34 = U1;
Il_3 = Ul_ers34 / Rl_ers34
Il_3 = 1.6667
Il_4 = Il_3
Il_4 = 1.6667
Ul_3 = Il_3 * Rl_3
Ul_3 = 7.5000
Ul_4 = Il_4 * Rl_4
Ul_4 = 2.5000
Schaltung 2:
Ir_1 = Ir_ges
Ir_1 = 1.4359
Ur_23 = Rr_ers23 * Ir_ges
Ur_23 = 4.1026
Ur_2 = Ur_23
Ur_2 = 4.1026
Ur_3 = Ur_23
Ur_3 = 4.1026
Ur_1 = U2 - Ur_23
Ur_1 = 7.8974
Ir_1 = Ur_1 / Rr_1
Ir_1 = 1.4359
Ir_2 = Ur_2 / Rr_2
Ir_2 = 0.4103
Ir_3 = Ur_3 / Rr_3
Ir_3 = 1.0256

d) Leistung

Schaltung 1:
Pl_1 = Ul_1 * Il_1
Pl_1 = 50
Pl_2 = Ul_2 * Il_2
Pl_2 = 25
Pl_3 = Ul_3 * Il_3
Pl_3 = 12.5000
Pl_4 = Ul_4 * Il_4
Pl_4 = 4.1667
Schaltung 2:
Pr_1 = Ur_1 * Ir_1
Pr_1 = 11.3399
Pr_2 = Ur_2 * Ir_2
Pr_2 = 1.6831
Pr_3 = Ur_3 * Ir_3
Pr_3 = 4.2078

e) Schalter

Ur_1_schalter = 0
Ur_1_schalter = 0

f) Amperemeter

Rr_3ers_innen = Rr_3 + R_innen
Rr_3ers_innen = 4.2500
Rr_ers23_innen = 1/sum(1 ./ [Rr_2 Rr_3ers_innen])
Rr_ers23_innen = 2.9825
Ir_ges_innen = U2 / (Rr_ers23_innen + Rr_1);
Ur_23_innen = Rr_ers23_innen * Ir_ges_innen
Ur_23_innen = 4.2192
Ir_2_innen = Ur_23_innen / Rr_2
Ir_2_innen = 0.4219
Ir_3_innen = Ur_23_innen / Rr_3
Ir_3_innen = 1.0548
Ur_innen = Ir_3_innen * R_innen
Ur_innen = 0.2637