Elektrostatik - Aufgabe 5
Gegeben:
clear
all
;
r1 = 1e-3;
%1mm
r2 = 1;
%1m
q1 = 5e-12;
%5 pC
q2 = 0.02e-9;
%0.02 nC
r3 = 0.1;
%Zusätzliche Kosntanten
e_0 = 8.854e-12;
%C^2 / (N m^2)
Potentiale
phi = @(q,r) q ./ (4*pi*e_0*r);
phi1 = phi(q1,r1)
phi1 = 44.9387
phi2 = phi(q1,r2)
phi2 = 0.0449
Spannung
U = phi1 - phi2
U = 44.8938
Energie
W1 = q1 * U
W1 = 2.2447e-10
Arbeit an Probeladung q2
W2 = q2 * phi(q1,r3)
W2 = 8.9877e-12